(2x+3)(5x^2-16x+12)=0

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Solution for (2x+3)(5x^2-16x+12)=0 equation: 


Simplifying
(2x + 3)(5x2 + -16x + 12) = 0

Reorder the terms:
(3 + 2x)(5x2 + -16x + 12) = 0

Reorder the terms:
(3 + 2x)(12 + -16x + 5x2) = 0

Multiply (3 + 2x) * (12 + -16x + 5x2)
(3(12 + -16x + 5x2) + 2x * (12 + -16x + 5x2)) = 0
((12 * 3 + -16x * 3 + 5x2 * 3) + 2x * (12 + -16x + 5x2)) = 0
((36 + -48x + 15x2) + 2x * (12 + -16x + 5x2)) = 0
(36 + -48x + 15x2 + (12 * 2x + -16x * 2x + 5x2 * 2x)) = 0
(36 + -48x + 15x2 + (24x + -32x2 + 10x3)) = 0

Reorder the terms:
(36 + -48x + 24x + 15x2 + -32x2 + 10x3) = 0

Combine like terms: -48x + 24x = -24x
(36 + -24x + 15x2 + -32x2 + 10x3) = 0

Combine like terms: 15x2 + -32x2 = -17x2
(36 + -24x + -17x2 + 10x3) = 0

Solving
36 + -24x + -17x2 + 10x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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